# Array Average Algorithm

Next, let’s look at how to get the average of all elements in an array. It’s going to build off of the array sum algorithm from last time and the code will look pretty similar.

``````public double average(int[] ray) {
int sum = 0;
for (int i = 0; i < ray.length; i++) {
sum += ray[i];
}
return (double)sum / ray.length;
}
``````

Most of the logic is the same as calculating the sum. In fact, we’re calculating the sum again. The difference is what we’re doing before it returns.

Notice that this method is returning a `double` instead of an `int`. We want the decimals, so we can’t use `int` here. But that also means that we have to do a little bit of work on the last line to get the average as a `double`.

If we just did `sum / ray.length`, both of which are `int` values, the result would be an `int` and any decimals would be truncated. Not what we want.

So what we do is add a cast do `sum` and it becomes `(double)sum`. Now it’s a `double` and we can divide it by `ray.length` and get a `double` as a result. We could have also cast `ray.length` or cast both and it would have worked the same way. We also could have used `double` instead of `int` for `sum` and it would have worked perfectly well.

## With a while loop

The same logic would work with a `while` loop.

``````public double average(int[] ray) {
double sum = 0;
int i = 0;
while (i < ray.length) {
sum += ray[i];
i++;
}
return sum / ray.length;
}
``````

This time I did make `sum` a `double` just so you could see it both ways.

## With a for each loop

And a for each would be fine as well.

``````public double average(int[] ray) {
double sum = 0;
for (int i : ray) {
sum += i;
}
return sum / ray.length;
}
``````

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